Mobile Notice
You appear to be on a device with a "narrow" screen width (i.e. you are probably on a mobile phone). Due to the nature of the mathematics on this site it is best views in landscape mode. If your device is not in landscape mode many of the equations will run off the side of your device (should be able to scroll to see them) and some of the menu items will be cut off due to the narrow screen width.
Assignment Problems Notice
Please do not email me to get solutions and/or answers to these problems. I will not give them out under any circumstances nor will I respond to any requests to do so. The intent of these problems is for instructors to use them for assignments and having solutions/answers easily available defeats that purpose.
If you are looking for some problems with solutions you can find some by clicking on the "Practice Problems" link above.
If you are looking for some problems with solutions you can find some by clicking on the "Practice Problems" link above.
Section 15.8 : Change of Variables
For problems 1 – 4 compute the Jacobian of each transformation.
- \(x = 4{u^2}v\hspace{0.25in}y = 6v - 7u\)
- \(x = \sqrt u \hspace{0.25in}\hspace{0.25in}y = 10u + v\)
- \(\displaystyle x = {v^3}u\hspace{0.25in}\hspace{0.25in}y = \frac{{{u^2}}}{v}\)
- \(x = {{\bf{e}}^u}\cos v\hspace{0.25in}y = {{\bf{e}}^u}\sin v\)
- If \(R\) is the region inside \(\displaystyle \frac{{{x^2}}}{{25}} + 49{y^2} = 1\) determine the region we would get applying the transformation \(x = 5u\), \(\displaystyle y = \frac{1}{7}v\) to \(R\).
- If \(R\) is the triangle with vertices \(\left( {2,0} \right)\), \(\left( {6,4} \right)\) and \(\left( {1,4} \right)\) determine the region we would get applying the transformation \(\displaystyle x = \frac{1}{5}\left( {u - v} \right)\), \(\displaystyle y = \frac{1}{5}\left( {u + 4v} \right)\) to \(R\).
- If \(R\) is the parallelogram with vertices \(\left( {0,0} \right)\), \(\left( {4,2} \right)\), \(\left( {0,4} \right)\) and \(\left( { - 4,2} \right)\) determine the region we would get applying the transformation \(x = u - v\), \(\displaystyle y = \frac{1}{2}\left( {u + v} \right)\) to \(R\).
- If \(R\) is the square defined by \(0 \le x \le 3\) and \(0 \le y \le 3\) determine the region we would get applying the transformation \(x = 3u\), \(y = v\left( {2 + {u^2}} \right)\) to \(R\).
- If \(R\) is the parallelogram with vertices \(\left( {1,1} \right)\), \(\left( {5,3} \right)\), \(\left( {8,8} \right)\) and \(\left( {4,6} \right)\) determine the region we would get applying the transformation \(\displaystyle x = \frac{6}{7}\left( {u - v} \right)\), \(\displaystyle y = \frac{1}{7}\left( {10u - 3v} \right)\) to \(R\).
- If \(R\) is the region bounded by \(xy = 4\), \(xy = 10\), \(y = x\) and \(y = 6x\) determine the region we would get applying the transformation \(\displaystyle x = 2\sqrt {\frac{u}{v}} \), \(y = 4\sqrt {uv} \) to \(R\).
- Evaluate \(\displaystyle \iint\limits_{R}{{{x^2}{y^4}\,dA}}\) where \(R\) is the region bounded by \(xy = 4\), \(xy = 10\), \(y = x\) and \(y = 6x\) using the transformation \(\displaystyle x = 2\sqrt {\frac{u}{v}} \), \(y = 4\sqrt {uv} \).
- Evaluate \(\displaystyle \iint\limits_{R}{{1 - y\,dA}}\) where \(R\) is the triangle with vertices \(\left( {0,4} \right)\), \(\left( {1,1} \right)\) and \(\left( {2,5} \right)\) using the transformation \(\displaystyle x = \frac{1}{7}\left( {7 + u - v} \right)\), \(\displaystyle y = \frac{1}{7}\left( {7 + 4u + 3v} \right)\) to \(R\).
- Evaluate \(\displaystyle \iint\limits_{R}{{121x\,dA}}\) where \(R\) is the parallelogram with vertices \(\left( {0,0} \right)\), \(\left( {6,2} \right)\), \(\left( {7,6} \right)\) and \(\left( {1,4} \right)\) using the transformation \(\displaystyle x = \frac{1}{{11}}\left( {v - 3u} \right)\), \(\displaystyle y = \frac{1}{{11}}\left( {4v - u} \right)\) to \(R\).
- Evaluate \(\displaystyle \iint\limits_{R}{{\frac{{15y}}{x}\,dA}}\) where \(R\) is the region bounded by \(xy = 2\), \(xy = 6\), \(y = 4\) and \(y = 10\) using the transformation \(x = v\), \(\displaystyle y = \frac{{2u}}{{3v}}\).
- Evaluate \(\displaystyle \iint\limits_{R}{{2y - 8x\,dA}}\) where \(R\) is the parallelogram with vertices \(\left( {6,0} \right)\), \(\left( {8,4} \right)\), \(\left( {6,8} \right)\) and \(\left( {4,4} \right)\) using the transformation \(\displaystyle x = \frac{1}{4}\left( {u - v} \right)\), \(\displaystyle y = \frac{1}{2}\left( {u + v} \right)\) to \(R\).
- Derive a transformation that will transform the ellipse \(\displaystyle \frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1\) into a unit circle.
- Derive the transformation used in problem 12.
- Derive the transformation used in problem 13.
- Derive a transformation that will convert the parallelogram with vertices \(\left( {4,1} \right)\), \(\left( {7,4} \right)\), \(\left( {6,8} \right)\) and \(\left( {3,5} \right)\) into a rectangle in the \(uv\) system.
- Derive a transformation that will convert the parallelogram with vertices \(\left( {4,1} \right)\), \(\left( {7,4} \right)\), \(\left( {6,8} \right)\) and \(\left( {3,5} \right)\) into a rectangle with one corner occurring at the origin of the \(uv\) system.