Mobile Notice
You appear to be on a device with a "narrow" screen width (i.e. you are probably on a mobile phone). Due to the nature of the mathematics on this site it is best views in landscape mode. If your device is not in landscape mode many of the equations will run off the side of your device (should be able to scroll to see them) and some of the menu items will be cut off due to the narrow screen width.
Assignment Problems Notice
Please do not email me to get solutions and/or answers to these problems. I will not give them out under any circumstances nor will I respond to any requests to do so. The intent of these problems is for instructors to use them for assignments and having solutions/answers easily available defeats that purpose.
If you are looking for some problems with solutions you can find some by clicking on the "Practice Problems" link above.
If you are looking for some problems with solutions you can find some by clicking on the "Practice Problems" link above.
Section 12.11 : Velocity and Acceleration
- An objects acceleration is given by \(\vec a = \cos \left( {2t} \right)\,\vec i + 4{t^3}\,\vec j + 6\sin \left( {3t} \right)\vec k\). The objects initial velocity is \(\vec v\left( 0 \right) = 6\,\vec i + 2\vec j + 7\vec k\) and the objects initial position is \(\vec r\left( 0 \right) = \vec i - 9\vec j + 6\vec k\). Determine the objects velocity and position functions.
- An objects acceleration is given by \(\vec a = 10t\,\vec i - 6\,\vec j + t\cos \left( t \right)\vec k\). The objects initial velocity is \(\vec v\left( 0 \right) = - \,\vec i + 11\vec j - \vec k\) and the objects initial position is \(\vec r\left( 0 \right) = 4\vec i + \vec j + 10\vec k\). Determine the objects velocity and position functions.
- Determine the tangential and normal components of acceleration for the object whose position is given by \(\vec r\left( t \right) = \left\langle {5t,1 - 2t,4{t^{\frac{3}{2}}}} \right\rangle \).
- Determine the tangential and normal components of acceleration for the object whose position is given by \(\vec r\left( t \right) = \left\langle {6,{{\bf{e}}^{ - 5t}},3t{{\bf{e}}^{ - 5t}}} \right\rangle \).