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Section 1.6 : Rational Expressions
10. Perform the indicated operation in the following expression.
\[\frac{x}{{{x^2} + 12x + 36}} - \frac{{x - 8}}{{x + 6}}\]Show All Steps Hide All Steps
Start SolutionWe first need the least common denominator for this rational expression. However, before we get that we’ll need to factor the denominator of the first term. Doing this gives,
\[\frac{x}{{{x^2} + 12x + 36}} - \frac{{x - 8}}{{x + 6}} = \frac{x}{{{{\left( {x + 6} \right)}^2}}} - \frac{{x - 8}}{{x + 6}}\] Show Step 2The least common denominator is then,
\[{\mbox{lcd : }}{\left( {x + 6} \right)^2}\]Remember that we only take the highest power on each term in the denominator when setting up the least common denominator.
Show Step 3Next, multiply each term by an appropriate quantity to get the least common denominator into the denominator of each term.
\[\frac{x}{{{x^2} + 12x + 36}} - \frac{{x - 8}}{{x + 6}} = \frac{x}{{{{\left( {x + 6} \right)}^2}}} - \frac{{\left( {x - 8} \right)\left( {x + 6} \right)}}{{\left( {x + 6} \right)\left( {x + 6} \right)}}\] Show Step 4Finally, all we need to do is the subtraction and simplify the numerator of the result.
\[\frac{x}{{{x^2} + 12x + 36}} - \frac{{x - 8}}{{x + 6}} = \frac{{x - \left( {x - 8} \right)\left( {x + 6} \right)}}{{{{\left( {x + 6} \right)}^2}}} = \frac{{x - \left( {{x^2} - 2x - 48} \right)}}{{{{\left( {x + 6} \right)}^2}}} = \require{bbox} \bbox[2pt,border:1px solid black]{{\frac{{48 + 3x - {x^2}}}{{{{\left( {x + 6} \right)}^2}}}}}\]