Section 3.8 : Derivatives of Hyperbolic Functions
3. Differentiate \(\displaystyle g\left( z \right) = \frac{{z + 1}}{{\tanh \left( z \right)}}\).
Show SolutionNot much to do here other than take the derivative using the formulas from class.
\[\require{bbox} \bbox[2pt,border:1px solid black]{{g'\left( z \right) = \frac{{\tanh \left( z \right) - \left( {z + 1} \right){{{\mathop{\rm sech}\nolimits} }^2}\left( z \right)}}{{{{\tanh }^2}\left( z \right)}}}}\]