Section 13.3 : Interpretations of Partial Derivatives
1. Determine if f(x,y)=xln(4y)+√x+y is increasing or decreasing at (−3,6) if
- we allow x to vary and hold y fixed.
- we allow y to vary and hold x fixed.
So, we want to determine the increasing/decreasing nature of a function at a point. We know that this means a derivative from our basic Calculus knowledge. Also, from the problem statement we know we want to allow x to vary while y is held fixed. This means that we will need the x partial derivative.
The x partial derivative and its value at the point is,
fx(x,y)=ln(4y)+12(x+y)−12→fx(−3,6)=ln(24)+12√3=3.4667So, we can see that fx(−3,6)>0 and so at (−3,6) if we allow x to vary and hold y fixed the function will be increasing.
b allow y to vary and hold x fixed Show Solution
This part is pretty much the same as the previous part. The only difference is that here we are allowing y to vary and we’ll hold x fixed. This means we’ll need the y partial derivative.
The y partial derivative and its value at the point is,
fy(x,y)=xy+12(x+y)−12→fy(−3,6)=−12+12√3=−0.2113So, we can see that fy(−3,6)<0 and so at (−3,6) if we allow y to vary and hold x fixed the function will be decreasing.
Note that, because of the three dimensional nature of the graph of this function we can’t expect the increasing/decreasing nature of the function in one direction to be the same as in any other direction!