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If you are looking for some problems with solutions you can find some by clicking on the "Practice Problems" link above.
If you are looking for some problems with solutions you can find some by clicking on the "Practice Problems" link above.
Section 1.1 : Functions
For problems 1 – 6 the given functions perform the indicated function evaluations.
- \(f\left( x \right) = 10x - 3\)
- \(f\left( { - 5} \right)\)
- \(f\left( 0 \right)\)
- \(f\left( 7 \right)\)
- \(f\left( {{t^2} + 2} \right)\)
- \(f\left( {12 - x} \right)\)
- \(f\left( {x + h} \right)\)
- \(h\left( y \right) = 4{y^2} - 7y + 1\)
- \(h\left( 0 \right)\)
- \(h\left( { - 3} \right)\)
- \(h\left( 5 \right)\)
- \(h\left( {6z} \right)\)
- \(h\left( {1 - 3y} \right)\)
- \(h\left( {y + k} \right)\)
- \(g\left( t \right) = \displaystyle \frac{{t + 5}}{{1 - t}}\)
- \(g\left( 0 \right)\)
- \(g\left( 4 \right)\)
- \(g\left( { - 7} \right)\)
- \(g\left( {{x^2} - 5} \right)\)
- \(g\left( {t + h} \right)\)
- \(g\left( {4\sqrt t + 9} \right)\)
- \(f\left( z \right) = \sqrt {4z + 5} \)
- \(f\left( 0 \right)\)
- \(f\left( { - 1} \right)\)
- \(f\left( { - 2} \right)\)
- \(f\left( {5 - 12y} \right)\)
- \(f\left( {2{z^2} + 8} \right)\)
- \(f\left( {z + h} \right)\)
- \(\displaystyle z\left( x \right) = \frac{{\sqrt {{x^2} + 9} }}{{4x + 8}}\)
- \(z\left( 4 \right)\)
- \(z\left( { - 4} \right)\)
- \(z\left( 1 \right)\)
- \(z\left( {2 - 7x} \right)\)
- \(z\left( {\sqrt {3x + 4} } \right)\)
- \(z\left( {x + h} \right)\)
- \(\displaystyle Y\left( t \right) = \sqrt {3 - t} - \frac{t}{{2t + 5}}\)
- \(Y\left( 0 \right)\)
- \(Y\left( 7 \right)\)
- \(Y\left( { - 4} \right)\)
- \(Y\left( {5 - t} \right)\)
- \(Y\left( {{t^2} - 10} \right)\)
- \(Y\left( {6t - {t^2}} \right)\)
The difference quotient of a function \(f\left( x \right)\) is defined to be,
\[\frac{{f\left( {x + h} \right) - f\left( x \right)}}{h}\]For problems 7 – 13 compute the difference quotient of the given function.
- \(Q\left( t \right) = 4 - 7t\)
- \(g\left( t \right) = 42\)
- \(H\left( x \right) = 2{x^2} + 9\)
- \(z\left( y \right) = 3 - 8y - {y^2}\)
- \(g\left( z \right) = \sqrt {4 + 3z} \)
- \(\displaystyle y\left( x \right) = \frac{{ - 4}}{{1 - 2x}}\)
- \(\displaystyle f\left( t \right) = \frac{{{t^2}}}{{t + 7}}\)
For problems 14 – 21 determine all the roots of the given function.
- \(y\left( t \right) = 40 + 3t - {t^2}\)
- \(f\left( x \right) = 6{x^4} - 5{x^3} - 4{x^2}\)
- \(Z\left( p \right) = 6 - 11p - {p^2}\)
- \(h\left( y \right) = 4{y^6} + 10{y^5} + {y^4}\)
- \(g\left( z \right) = {z^7} + 6{z^4} - 16z\)
- \(f\left( t \right) = {t^{\frac{1}{2}}} - 8{t^{\frac{1}{4}}} + 15\)
- \(\displaystyle h\left( w \right) = \frac{w}{{4w + 5}} + \frac{{3w}}{{w - 8}}\)
- \(\displaystyle g\left( w \right) = \frac{w}{{w + 3}} - \frac{{w + 2}}{{4w - 1}}\)
For problems 22 – 30 find the domain and range of the given function.
- \(f\left( x \right) = {x^2} - 8x + 3\)
- \(z\left( w \right) = 4 - 7w - {w^2}\)
- \(g\left( t \right) = 3{t^2} + 2t - 3\)
- \(g\left( x \right) = 5 - \sqrt {2x} \)
- \(B\left( z \right) = 10 + \sqrt {9 + 7{z^2}} \)
- \(h\left( y \right) = 1 + \sqrt {6 - 7y} \)
- \(f\left( x \right) = 12 - 5\sqrt {2x + 9} \)
- \(V\left( t \right) = - 6\left| {5 - t} \right|\)
- \(y\left( x \right) = 12 + 9\left| {{x^2} - 1} \right|\)
For problems 31 – 51 find the domain of the given function.
- \(\displaystyle f\left( t \right) = \frac{{4 - 12t + 8{t^2}}}{{16t + 9}}\)
- \(\displaystyle v\left( y \right) = \frac{{{y^3} - 27}}{{4 - 17y}}\)
- \(\displaystyle g\left( x \right) = \frac{{3x + 1}}{{5{x^2} - 3x - 2}}\)
- \(\displaystyle h\left( t \right) = \frac{{{t^3} - {t^2} + 1 - 1}}{{35{t^3} + 2{t^4} - {t^5}}}\)
- \(\displaystyle f\left( z \right) = \frac{{{z^2} + z}}{{{z^3} - 9{z^2} + 2z}}\)
- \(\displaystyle V\left( p \right) = \frac{{3 - {p^4}}}{{4{p^2} + 10p + 2}}\)
- \(g\left( z \right) = \sqrt {{z^2} - 15} \)
- \(f\left( t \right) = \sqrt {36 - 9{t^2}} \)
- \(A\left( x \right) = \sqrt {15x - 2{x^2} - {x^3}} \)
- \(Q\left( y \right) = \sqrt {4{y^3} - 4{y^2} + y} \)
- \(\displaystyle P\left( t \right) = \frac{{{t^2} + 7}}{{\sqrt {6t - {t^2}} }}\)
- \(\displaystyle h\left( t \right) = \frac{{{t^2}}}{{\sqrt {5 + 3t - {t^2}} }}\)
- \(\displaystyle h\left( x \right) = \frac{6}{{\sqrt {{x^2} - 7x + 3} }}\)
- \(\displaystyle f\left( z \right) = \frac{{z + 1}}{{\sqrt {{z^4} - 6{z^3} + 9{z^2}} }}\)
- \(S\left( t \right) = \sqrt {8 - t} + \sqrt {2t} \)
- \(g\left( x \right) = \sqrt {5x - 8} - 2\sqrt {x + 9} \)
- \(h\left( y \right) = \sqrt {49 - {y^2}} - \frac{y}{{\sqrt {4y - 12} }}\)
- \(\displaystyle A\left( x \right) = \frac{{x + 1}}{{x - 4}} + 4\sqrt {{x^2} + 10x + 9} \)
- \(\displaystyle f\left( t \right) = \frac{8}{{{t^2} - 3t - 4}} + \frac{3}{{\sqrt {12 - 7t - 3{t^2}} }}\)
- \(\displaystyle R\left( x \right) = \frac{3}{{{x^4} + {x^2}}} + \sqrt[5]{{{x^2} - x - 6}}\)
- \(C\left( z \right) = {z^3} - \sqrt[4]{{{z^6} + {z^2}}}\)
For problems 52 – 55 compute \(\left( {f \circ g} \right)\left( x \right)\) and \(\left( {g \circ f} \right)\left( x \right)\) for each of the given pairs of functions.
- \(f\left( x \right) = 5 + 2x\), \(g\left( x \right) = 8 - 23x\)
- \(f\left( x \right) = \sqrt {2 - x} \), \(g\left( x \right) = 2{x^2} - 9\)
- \(f\left( x \right) = 2{x^2} + x - 4\), \(g\left( x \right) = 7x - {x^2}\)
- \(\displaystyle f\left( x \right) = \frac{x}{{3 + 2x}}\), \(g\left( x \right) = 8 + 5x\)