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Section 5.2 : Computing Indefinite Integrals

5. Evaluate \( \displaystyle \int{{12\,dy}}\).

Show Solution

There really isn’t too much to do other than to evaluate the integral.

\[\int{{12\,dy}} = \require{bbox} \bbox[2pt,border:1px solid black]{{12y + c}}\]

Don’t forget to add on the “+c” since we know that we are asking what function did we differentiate to get the integrand and the derivative of a constant is zero and so we do need to add that onto the answer.