Section 3.6 : Derivatives of Exponential and Logarithm Functions
5. Differentiate \(\displaystyle h\left( y \right) = \frac{y}{{1 - {{\bf{e}}^y}}}\) .
Show SolutionNot much to do here other than take the derivative using the formulas from class. \[h'\left( y \right) = \frac{{\left( 1 \right)\left( {1 - {{\bf{e}}^y}} \right) - y\left( { - {{\bf{e}}^y}} \right)}}{{{{\left( {1 - {{\bf{e}}^y}} \right)}^2}}} = \require{bbox} \bbox[2pt,border:1px solid black]{{\frac{{1 - {{\bf{e}}^y} + y\,{{\bf{e}}^y}}}{{{{\left( {1 - {{\bf{e}}^y}} \right)}^2}}}}}\]