First, using our calculator we can see that,

\[4x = {\cos ^{ - 1}}\left( { - \frac{1}{7}} \right) = 1.7141\]

Now we’re dealing with cosine in this problem and we know that the \(x\)-axis represents cosine on a unit circle and so we’re looking for angles that will have a \(x\) coordinate of \( - \frac{1}{7}\). This means that we’ll have angles in the second (this is the one our calculator gave us) and third quadrant. Here is a unit circle for this situation.

From the symmetry of the unit circle we can see that we can either use –1.7141 or \(2\pi - 1.7141 = 4.5691\) for the second angle. Each will give the same set of solutions. However, because it is easy to lose track of minus signs we will use the positive angle for our second solution.

Show Step 3

From the discussion in the notes for this section we know that once we have these two angles we can get all possible angles by simply adding “\( + \,2\pi n\) for \(n = 0, \pm 1, \pm 2, \ldots \)” onto each of these.

This then means that we must have,

\[4x = 1.7141 + 2\pi n\hspace{0.25in}{\mbox{OR }}\hspace{0.25in}4x = 4.5691 + 2\pi n\hspace{0.25in}n = 0, \pm 1, \pm 2, \ldots \]

Finally, to get all the solutions to the equation all we need to do is divide both sides by 4.

\[\require{bbox} \bbox[2pt,border:1px solid black]{{x = 0.4285 + \frac{{\pi n}}{2}\hspace{0.25in}{\mbox{OR }}\hspace{0.25in}x = 1.1423 + \frac{{\pi n}}{2}\hspace{0.25in}n = 0, \pm 1, \pm 2, \ldots }}\]

Note that depending upon the amount of decimals you used here your answers may vary slightly from these due to round off error. Any differences should be slight and only appear around the 4^th decimal place or so however.