Section 9.6 : Polar Coordinates
13. Sketch the graph of the following polar equation.
\[r = 9\sin \theta \] Show SolutionWe can rewrite this as,
\[r = 2\left( {\frac{9}{2}} \right)\sin \theta \]and so we know from the notes on this section that this is simply the circle with radius \(\frac{9}{2}\) and center \(\left( {0,\frac{9}{2}} \right)\).
So here is the graph of this function.
